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# SBI PO Quantitative Aptitude Quiz 1

IBPS EXAM Guru

1 . Directions (1–8): What approximate value should come in place of the question mark (?) in the following? (You are not expected to calculate the exact value).
8787 ÷ 343 × $\sqrt 50$ = ?

 A.   100 B.   250 C.   180 D.   100
2 . $\sqrt [3]{54821}$ × (303 ÷ 8) = $(?)^2$

 A.   48 B.   38 C.   28 D.   18
3 . $5\over8$ of 4011.33 +$7\over10$ of 3411.22 = ?

 A.   4810 B.   4820 C.   4890 D.   4860
4 . 23% of 6783 + 57% of 8431 = ?

 A.   6460 B.   6420 C.   6480 D.   6360
5 . Ratio of cost price and marked price of an article is 3:5. Ratio of profit percentage and discount percentage is 5:3. Find discount percentage?

 A.   10% B.   10÷3 C.   20% D.   5%
6 . A can do a piece of work in the days taken by B and C together A and B can do piece of work in 10 days and C can do in 50 days. Find in how many days B alone can complete the work?

 A.   25 B.   35 C.   45 D.
7 . 10 year ago A was 3 times of the age of B and hence, after 10 years, he will be twice the age of B. Find the respective ratio of their present age.

 A.   7:3 B.   3:7 C.   1:2 D.   2:1
8 . A boat goes in a running water flowing at the rate of 1.5 kmph. In a given time, boat goes twice the distance in downstream than upstream. Find speed of the boat in still water.

 A.   4.5 B.   3 C.   5 D.   None of the Above
9 . If a train is going at the rate of 40 kmph, it is late by 11 min. If it is going at the rate of 50 kmph, it is late by 5 mins to reach at a destination. Find actual time to complete the journey.

 A.   30min. B.   35min C.   19min D.   None of the above

1 .

 Answer : Option C Explanation : ═ ? =$8787\over 343$ × $\sqrt 50$ = 25.62 × 7= 26 × 7 = 182 180
2 .

 Answer : Option B Explanation : $\sqrt [3]{54821}$× (303 ÷ 8) = $(?)^2$ $\sqrt [3]{54821}$ X [$303\over8$] $(?)^2$ = 38 × 38? = 38
3 .

 Answer : Option C Explanation : (3) ? = 4011.33 × $5\over8$+3411.22 × $7\over10$ = 501.41× 5 + 341.12 × 7= 2507 + 2387= 4894 = 4890
4 .

 Answer : Option D Explanation : (5) ? = 6783 × $23\over100$+ 8431 × $57\over100$ = ?$156009\over100$ + $4805670\over100$ = $636576\over100$ =6365.76= 6360
5 .

 Answer : Option C Explanation : C.P. : M.R.P3x : 5xP% : D%5y : 3yS.P. = S.P.3x + $3x+5y\over100$ = 5x + $5x+3y\over100$Y= $20\over3$D% = 3y = 20%
6 .

 Answer : Option A Explanation :
7 .

 Answer : Option A Explanation : A : B3 : 1 – 10 years before2 : 1 – After 10 yearsequating difference we get So, 3 unit = 60 yearsThus, in present A and B's age is 70 yearsand 30 years respectively.ratio = 7 : 3.
8 .

 Answer : Option A Explanation : (1) As, the time is equal for downstream and upstream distance. Now,,$Distance\over speed$ = $29(Distance)\over speed$ $X\over M-1.5$ = $2X\over M+1.5$M = 4.5
9 .

 Answer : Option A Explanation : x = Actual time in minutes.S × T = S × T40 × $X+11\over60$ = 50 × $X+5\over60$x = 19 minutes.