| Answers & Solutions | | 1 . | Answer : Option B | Explanation : | Reqd amount = $44\over0.88$ = 50 quintals | | | 2 . | Answer : Option C | Explanation : | Let the speed of the slower motorcyclist be x km/hr. Therefore the speed of the faster motorcyclist will be (x + 5) km/hr. In 2 hrs both motorcylists cover 2x + 2(x + 5) = (4x + 10) km distance. i.e. 4x + 10 = 220 - 30 or, 4x = 180 or, x = 45 Ratio = 50 : 45 = 10 : 9
| | | 3 . | Answer : Option A | Explanation : | Let original area ploughed daily = x hectares
Total area ploughed = 16x
If (x + 18) hectares is ploughed daily, then total area = 10(x + 18)
Given that, 16x = 10(x + 18)
or, x = 30 hectares
total area of field = 16 × 30 = 480 hectares
| | | 4 . | Answer : Option D | Explanation : | | | | 5 . | Answer : Option D | Explanation : | | | | 6 . | Answer : Option C | Explanation : | | | | 7 . | Answer : Option D | Explanation : | | | | 8 . | Answer : Option D | Explanation : | In a three-digit no. with 7 at unit’s place, zero can’t be there at hundred’s place. So, hundred’s place can be filled with any of the digits from 1 to 9. Thus there are 9 options. Ten’s place = digits 0 to 9 = 10 options Unit’s place = 7 = 1 option no. of required numbers = 9 × 10 × 1 = 90
| | | 9 . | Answer : Option D | Explanation : | | | | 10 . | Answer : Option A | Explanation : | ? = $725\over 25$ x 13 = 29 - 13 = 16 | | | | |
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