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# SBI PO Quadratic Equation Questions and Answers Quiz

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SBI PO Quadratic Equation Questions and Answers Quiz

1 . Directions (Q. 1-5): Two equations (I) and (II) are given in each question. On the basis of these equations you have to decide the relation between ‘x’ and ‘y’ and give answer.

(1) if x > y
(2) if x < y
(3) if x $\geq$ y
(4) if x $\leq$ y
(5) if x = y or no relation can be established between ‘x’ and ‘y’.

$Q.$ I. $6x^ 2 - 19x + 15 = 0$
II.$10y^ 2 - 29y + 21 = 0$

 A.   x > y B.   x < y C.   x $\geq$ y D.   x $\leq$ y
2 . I. 12 $x^ 2$ + 11x - 56 = 0
II. 4 $y^ 2$ - 15y + 14 = 0

 A.   x > y B.   x < y C.   x $\geq$ y D.   x $\leq$ y
3 . I. $3x 2 + 13x + 12$= 0
II.$y^ 2 + 9y + 20$= 0

 A.   x > y B.   x < y C.   x $\geq$ y D.   x $\leq$ y
4 . I. $8x^ 2$ - 15x + 7 = 0
II. $2y^ 2$ - 7y + 6 = 0

 A.   x > y B.   x < y C.   x $\geq$ y D.   x $\leq$ y
5 . I. 7x - 3y = 13
II. 5x + 4y = 40

 A.   x > y B.   x < y C.   x $\geq$ y D.   x $\leq$ y
6 . I.$2x^ 2$ - 11x + 15 = 0
II.$21y^2$ - 23y + 6 = 0

 A.   x > y B.   x < y C.   x $\geq$ y D.   x = y or no relation can be established between ‘x’ and ‘y’.
7 . I. $5x^ 2$ - 16x + 11= 0
II. $5y^ 2$ - 3y - 2 = 0

 A.   x>y B.   x $\geq$ y C.   x< td> D.   x $\leq$ y
8 . I. $x^ 2$ + 11x + 28 = 0
II. $2y^ 2$ + 13y + 20 = 0

 A.   x > y B.   x < y C.   $x \geq y$ D.   $x \leq y$
9 . I. $6x^ 2$ + 29x + 35 = 0
II. $3y^ 2$ + 19y + 30 = 0

 A.   $x > y$ B.   $x < y$ C.   $x \geq y$ D.   $x \leq y$
10 . I. 2x + 5y = 6
II. 5x + 11y = 9

 A.   $x > y$ B.   $x < y$ C.   $x \geq y$ D.   $x \leq y$
Answers & Solutions

1 .
 Answer : Option C Explanation : $6x^ 2 - 19x + 15 = 0 $$3x(2x - 3) - 5(2x - 3) = 0 (3x - 5) (2x - 3) = 0 x = 5\over 3 , 3\over 2$$10y 2 - 15y - 14y + 21 = 0$$5y(2y - 3) - 7(2y - 3) = 0$$(5y - 7) (2y - 3) = 0$y = $7\over5$ , $3\over 2$$x \geq y 2 .  Answer : Option D Explanation : I. 12 x^ 2 + 32x - 21x - 56 = 0or, 4x(3x + 8) - 7(3x + 8) = 0or, (4x - 7) (3x + 8) = 0X = 7\over 4 , -8\over 3II. 4y^ 2 - 8y - 7y + 14 = 0or, 4y(y - 2) - 7(y - 2) = 0or, (4y - 7) (y - 2) = 0y = 2, 7\over 4$$x \leq y$
3 .
 Answer : Option A Explanation : I . $3x^ 2$ + 9x + 4x + 12 = 0or, 3x(x + 3) + 4(x + 3) = 0or, (3x + 4) (x + 3) = 0x = $-4\over 3$, -3II.$y^ 2$ + 5y + 4y + 20 = 0or, y(y + 5) + 4(y + 5) = 0or, (y + 4) (y + 5) = 0y = - 4, - 5$x > y$
4 .
 Answer : Option B Explanation : I. $8x^ 2$ - 8x - 7x + 7 = 0or, 8x(x - 1) -7(x - 1) = 0or, (8x - 7) (x - 1) = 0x = $7\over 8$ , 1II. $2y^ 2$ - 4y - 3y + 6 = 0or, 2y(y - 2) -3(y - 2) = 0or, (y - 2) (2y - 3) = 0y = 2 , $3\over 2$$x < y 5 .  Answer : Option B Explanation : Eqn (I) × 4 + Eqn (II) × 3 28x - 12y = 5215x + 12y = 120-----------------------43x \,\,\,\,\,\,\,\,\,\,\, = 172-----------------------x = 4 & y = 5 x < y 6 .  Answer : Option A Explanation : I. 2x^ 2 - 6x - 5x + 15 = 0or,2x(x - 3) - 5(x - 3) = 0or, (2x - 5) (x - 3) = 0x = 3 , 5\over 2II. 21y^ 2 - 14y - 9y + 6 = 0or,7y(3y - 2) - 3 (3y - 2) = 0or,(7y - 3)(3y - 2) = 0y = 3\over 7 , 2\over 3$$x > y$
7 .
 Answer : Option B Explanation : I. $5x^ 2$ - 5x - 11x + 11 = 0or,5x(x - 1) - 11(x - 1) = 0or,(x - 1) (5x - 11) = 0x = 1 , $11\over 5$II. $5y^ 2$ - 5y + 2y - 2 = 0or, 5y (y - 1) + 2(y - 1) = 0or, (5y + 2)(y - 1) = 0y = 1 , - $2\over 5$x $\geq$ y
8 .
 Answer : Option D Explanation : I. $x^ 2$ + 4x + 7x + 28 = 0or, x(x + 4) +7(x + 7) = 0or, (x + 4) (x + 7) = 0x = - 4, - 7II. $2y^ 2$ + 8y + 5y + 20 = 0or, 2y(y + 4) + 5(y + 4) = 0or, (y + 4) (2y + 5) = 0y = -4, -$5\over 2$x $\leq$ y
9 .
 Answer : Option A Explanation : I. $6x ^ 2$ + 15x + 14x + 35 = 0or, 3x(2x + 5) + 7(2x + 5) = 0or,(3x + 7) (2x + 5) = 0x = - $7\over 3$ , - $5\over 2$II. $3y^ 2$ + 9y + 10y + 30 = 0or, 3y(y + 3) +10(y + 3) = 0or,(3y + 10) (y + 3) = 0y = 3, -$10\over 3$$x > y$
10 .
 Answer : Option B Explanation : eq (I) × 5 - eq (II) × 210x + 25y = 3010x ± 22y = 18- $\,\,\,\,\,\,$ - $\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,$- ---------------------$\,\,\,\,\,\,\,\,\,\,\,$ 3y = 12y = 4 and x = - 7 $x < y$