# IBPS PO 2017 Quantitative aptitude Practice Quiz 51

1 .

 A.   4474 B.   4734 C.   4324 D.   4564
2 . What is the ratio of average number of students appeared in 2009 and 2012 ?

 A.   69292 : 69432 B.   69436 : 69643 C.   69293 : 69436 D.   69463 : 69293
3 . Approximately what is the average number of candidate qualified from Haryana from all the years ?

 A.   4418 B.   4287 C.   4217 D.   4116
4 . What is the difference between maximum number of candidate appeared from Patna and minimum number of candidate appeared from Kolkata from all the years ?

 A.   79668 B.   79686 C.   78966 D.   79669
5 . In which year the minimum number of candidate qualified from Chennai ?

 A.   2011 B.   2010 C.   2013 D.   2006
6 .

 A.   177.77% B.   176.78 % C.   178.87% D.   180.82%
7 . What is the total number of player participating in Cricket from country 4, 5 and 6 and the number of players participating in Football from country 1, 2 and 3 ?

 A.   335 B.   635 C.   435 D.   535
8 . In which country in the number of player participating in Football is the highest and number of player participating in Badminton is the lowest ?

 A.   Country 3 and 2 B.   Country 4 and 6 C.   Country 3 and 4 D.   Country 5 and 1
9 . The number of player participating in Badminton from all the country is what percent of total number of player participating in all game from country – 3 ?

 A.   134 % B.   164 % C.   126 % D.   157 %
10 . 60 % of players participating in all game from country 5 is male and 30 % players participating in all game from country 3 is female. What will be their ratio ?

 A.   127 : 170 B.   13 : 7 C.   49 : 27 D.   87 : 55

1 .
 Answer : Option A Explanation : Approximate number of candidate qualified from Lucknow=$7\over100$x35874=2511.18 ≈ 2511From chennai =$6\over100$x13650=819From Haryana =$4\over100$x28612=1144.48 ≈ 1144Total =2511+819+1144=4474
2 .
 Answer : Option C Explanation : Total number of student appeared in 2009 = 485049Average=$485049\over7$=69292.71≈69293Average number of student appeared in 2012=$486052\over7$=69436=69293:69436
3 .
 Answer : Option D Explanation :
4 .
 Answer : Option D Explanation : Maximum number of candidate from Patna = 89721Maximum number of candidate appeared from Kolkata = 10052Difference = 89721 – 10052 = 79669
5 .
 Answer : Option A Explanation :
6 .
 Answer : Option A Explanation : Number of players participating in Cricket from country 4 = 80Number of Players participating in Badminton from country 1 = 45percentage =$80\over45$x100=177.77
7 .
 Answer : Option C Explanation : Players participating in Cricket from country ( 4, 5 and 6) = (80 + 70 + 60) = 210Players participating in Football from country (1, 2 and 3)= (65 + 70 + 90) = 225Total = 210 + 225 = 435
8 .
 Answer : Option A Explanation : Country 3 has highest number of player in Football and country 2 has lowest number of players in Badminton.
9 .
 Answer : Option D Explanation : Total number of players participating in Badminton = ( 45+ 40 + 95 + 85 +95 + 65) = 425Number of player participating in all game from country 3 = ( 90 + 85 + 95) = 270percentage =$425\over270$x100=157.4 ≈ 157%
10 .
 Answer : Option C Explanation : Total number of players participating in all game from country 5 = (80 + 70 + 95) = 24560 % of 245 = 147 Total number of players participating in all game from country 3 = (90 + 85 + 95) = 270 30%of 270=81 ratio=$147\over81$=$49\over27$