# SBI PO Simplification Questions and Answers Quiz 5

1 . Directions (1-5): What will come in place of the question mark (?) in the following questions?

$Q.$ (5 × 7)%of (34 × 55) + 456.60 = 699.1 + ?

 A.   412 B.   422 C.   418 D.   428
2 . $14 \times 627 \div \sqrt{1089} = (?)^3 + 141$

 A.   5$\sqrt{5}$ B.   (125)$^3$ C.   25 D.   5
3 . 2$1.5\over5$ + 2$1\over6$ - 1$3.5\over15$ = $(?)^{1\over3}\over4$ + 1$7\over 30$

 A.   2 B.   8 C.   512 D.   324
4 . (80 x 0.40)$^3$$\div(40 x 1.6)^3$$\times$(128)$^ 3$ = (2)$^{? + 7}$

 A.   25 B.   11 C.   12 D.   18
5 . $(\sqrt{7} + 11)^2 = (?)^{1\over 3}$ + 2$\sqrt{847}$ + 122

 A.   36 + 44$\sqrt{7}$ B.   6 C.   216 D.   36
6 . Directions (6-10): What will come in place of the question mark (?) in the following questions?

$Q.$ $1\over 6$ of 92 $\div$ of 1$1\over23$ of (650) = 85 + ?

 A.   18 B.   21 C.   19 D.   28
7 . 92 x 576 $\div (\sqrt{1296}) = (?)^3 + \sqrt{49}$

 A.   3 B.   (9)$^2$ C.   9 D.   27
8 . 3$1\over 4$ + 2$1\over 2$ - 1$5\over 6$ = $(?)^2\over 10$ + 1$5\over 12$

 A.   25 B.   $\sqrt{5}$ C.   15 D.   5
9 . $(\sqrt{8}\times\sqrt{8})^{1\over 2} + (9)^{1\over2} = (?)^3 + \sqrt{8} - 340$

 A.   7 B.   19 C.   18 D.   9
10 . $(15 \times 0.40)^4\div(1080 \div 30)^4 \times(27 \div 8)^4 = (3 \times 2)^{? + 5}$

 A.   8 B.   3 C.   12 D.   16

1 .
 Answer : Option A Explanation : $34\times55\times5\times7\over100$ + 456.60 = 699.1 + ?$\Rightarrow$654.50 + 456.60 = 699.1 + ?$\Rightarrow$1111.1 = 699.1 + ?$\Rightarrow$? = 1111.1 – 699.1 = 412
2 .
 Answer : Option D Explanation : 14 × 627 ÷ 33$\Rightarrow$$?^ 3 + 141\Rightarrow 14\times627\over33 - 141 = ?^3$$\Rightarrow$266 – 141 = ?$^3$$\Rightarrow125 = ?^3? = \sqrt[3]{125} = \sqrt[3]{5\times5\times5} = 5 3 .  Answer : Option C Explanation : 2 + 1.5\over5 + 2 + 1\over6 - 1 - 3.5\over15 = (?)^{1\over3}\over4 + 1 + 7\over 30$$\Rightarrow$ 2 + $15\over50$ + 2 + $1\over6$ - 1 - $35\over 150$ - 1 - $7\over 30$ = $(?)^{1\over3}\over4$$\Rightarrow( 2 + 2 - 1 - 1 ) + 3\over 10 + 1\over 6 - 7\over 30 - 7\over 30 = (?)^{1\over3}\over4$$\Rightarrow$2 + [$9 + 5 - 7 - 7 \over 30$] = $(?)^{1\over3}\over4$ $\Rightarrow$2 + 0 = $(?)^{1\over3}\over4$$\Rightarrow (?)^{1\over3} = 2 x 4 = 8 \Rightarrow? = 8^3 = 8 x 8 x 8 = 512 4 .  Answer : Option B Explanation : (80 x 0.40)^3$$\div$(40 x 1.6)$^3$$\times(128)^ 3 = (2)^{? + 7}$$\Rightarrow$(32)$^3$$\div(64)^3$$\times$(128)$^ 3$ = (2)$^{? + 7}$$\Rightarrow$$(2^5)^3$$\div$$(2^6)^3$$\times$$(2^7)^ 3$ = (2)$^{? + 7}$$\Rightarrow$$(2^{15})\div (2^{18})\times(2^{21})$ = (2)$^{? + 7}$$\Rightarrow$$(2^{15 - 18 + 21})$ = (2)$^{? + 7}$$\Rightarrow$$(2^{18})$ = (2)$^{? + 7}$$\Rightarrow18 = ? + 7\Rightarrow? = 18 - 7 = 11Here, [ (a^m)^n = a^{mn} ; \,\,\, a^m \times a^n = a^{m + n} ; \,\,\, a^m \div a^n = a^{m - n} ] 5 .  Answer : Option C Explanation : (\sqrt{7} + 11)^2 = (?)^{1\over 3} + 2\sqrt{847} + 122\Rightarrow (\sqrt{7})^2 + (11)^2 + 2\sqrt{7} \times 11 = (?)^{1\over 3} + 2\sqrt{847} + 122\Rightarrow (?)^{1\over 3} = 128 - 122 = 6? = 6 x 6 x 6 = 216 6 .  Answer : Option C Explanation : 650 \times 24\over 23 \times 92\over 100 \times 1\over 6 = 85 + ?\Rightarrow 104 = 85 + ? \Rightarrow ? = 104 - 85 = 19 7 .  Answer : Option C Explanation : 92 x 576 \div (\sqrt{1296}) = (?)^3 + \sqrt{49}$$\Rightarrow$ 92 x 576 $\div (\sqrt{1296}) = (?)^3 + 7$$\Rightarrow 736 = ?^3 + 7\Rightarrow ?^3 = 736 - 7 = 729 = 9^3 \Rightarrow ?^3 = (9^3)^{1\over3} = 9 8 .  Answer : Option D Explanation : 3 + 1\over 4 + 2 + 1\over 2 - 1 - 5\over 6 = (?)^2 \over 10 + 1 + 5\over 12$$\Rightarrow$ 3 + 2 - 1 - 1 + $[$ $1\over 4$ + $1\over 2$ - $5\over 6$ - $5\over 12$ $]$ = $(?)^2\over 10$$\Rightarrow 3 + [ 3 + 6 - 10 - 5 \over 12 ] = ?^2\over 10$$\Rightarrow$ 3 - $1\over 2$ = $?^2\over 10$$\Rightarrow 5\over 2 = ?^2\over 10$$\Rightarrow$ $?^2$ = $5 \times 10 \over 2$ = 25? = $\sqrt{25}$ = 5
9 .
 Answer : Option A Explanation : $(\sqrt{8}\times\sqrt{8})^{1\over 2} + (9)^{1\over2} = (?)^3 + \sqrt{8} - 340$$\Rightarrow 8^{1\over 2} + 3 = (?)^3 + 8{1\over2} - 340\Rightarrow = 340 + 3 = 343? = \sqrt[3]{343} = 7 10 .  Answer : Option B Explanation : (15 \times 0.40)^4\div(1080 \div 30)^4 \times(27 \div 8)^4 = (3 \times 2)^{? + 5}$$\Rightarrow$ $6^4 \div (36)^4 \times (216)^4 = (3 \times 2)^{? + 5}$$\Rightarrow 6^4 \div (6)^8 \times (6)^12 = (6)^{? + 5}$$\Rightarrow$ $6^{4 - 8 + 12} = (6)^{? + 5}$$\Rightarrow 6^{8} = (6)^{? + 5}$$\Rightarrow$ ? + 5 = 8$\Rightarrow$ ? = 8 - 5 = 3