of same type ?

1) 18 days 2) 21 days 3) 3 days 4) 6 days 5) None of the above

Solution: ( 1).

We have the important relation, more work , more time ( days)

Since A piece of work can be done in 6 days

Therefore three times of work of same type can be done in 6 x 3 = 18 days

2. A, B and C can complete a work in 2 h. If A does the job alone in 6 h and B in 5 h , how long will it

take for C to finish the job alone ?

1) 5 ½ h 2) 7 ½ h 3) 9 h 4) 4 ½ h 5) None of the above

Solution: (2).

Let C alone can finish the job in x h.

According to the question,

Work done by A , B and C in 1 h = ½

= 1/6 + 1/5 + 1/x = ½

= 1/x = ½ - 1/6 – 1/5 = ( 15 -5-6) / 30

= 4/30 = 2/15

Therefore x = 7 ½ h

3. A and B together can complete a work in 3 days. They started together but after 2 days, B left the

work. If the work is completed after 2 more days, B alone could do the work in how many days ?

1) 5 2) 6 3) 7 4) 10 5) None of the above

Solution: (2)

( A+B )’s 2 day’s work = 2 x 1/3 = 2/3

Remaining work = 1 – 2/3 = 1/3

A will complete 1/3 work in 2

A will complete 1 work in 6

A’ s 1 day’s work = 1/6

B’s 1 day’s work = 1/3 - 1/6 = 1/6

Therefore B will take 6 days to complete the work alone

4. P and Q can finish a work in 30 days. They worked at it for 10 days and then Q left . The remaining

work is done by P alone in 20 more days. How long will P take to finish the work alone?

1) 30 days 2) 20 days 3) 60 days 4) 50 days 5) None of the above

Solution: (1)

( P + Q ) ‘s 10 day’s work = 1/30 x 10 = 1/3

Remaining work = ( 1 – 1/3 ) = 2/3

2/3 work is done by P in 20

Therefore whole work is done by P in

20 x 3/2 = 30 days

5. If 5 boys take 7 h to pack 35 toys, how many boys can pack 65 toys in 3 h ?

1) 26 2) 39 3) 45 4) 65 5) None of the above

Solution: (5).

Given , M1 = 5, M2 = ?, T1 = 7, T2 = 3,

W1 = 35 and W2 = 65

According to the formula ,

M1T1W2 = M2T2W1

= 5 x 7 x 65 = M2 x 3 x 35

Therefore M2 = ( 5 x 7 x 65 ) / ( 35 x 3) = 65 / 3 boys

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