he takes 4 min to cross the bridge?

1) 3600 m 2) 2800 m 3) 3500 m 4) 4500 m 5) None of these

Solution: (1)

Length of the bridge = Distance travelled by the person in 4 min

= Speed x Time

Speed = 54 km/h = 54 x 5/8 = 3 x 5 = 15 m/s

Time = 4 min = 4 x 60 = 240 s

Therefore required length = 15 x 240 = 3600m

2. Two men start together to walk a certain distance, one at 4 km/h and another at 3 km/h. the

former arrives half an hour before the latter. Find the distance.

1) 6 km 2) 9 km 3) 8 km 4) 7 km 5) None of these

Solution: (1).let total distance = x km

According to the question,

x/3 - x/4 = ½ ; x/12 = ½ = x = 6 km

3. Moving 6/7 of its usual speed a train is 10 min late. Find its usual time to cover the journey.

1) 25 min 2) 15 min 3) 35 min 4) 60 min 5) None of these

Solution: (4).

New speed = 6/7 of usual speed

Now, time taken = 7/6 of usual time

(7/6 of the usual time) – (usual time) = 10 min

= 1/6 of the usual time = 10 min

Therefore usual time = 60 min

4. A student walks from his house at 2 ½ km/h and reaches his school late by 6 min. Next day, he

increases his speed by 1 km/h and reaches 6 min before school time. How far is the school from his

house?

1) 5/4 km 2) 7/4 km 3) 9/4 km 4) 11/4 km 5) None of these

Solution: (2).

Let the required distance = x

According to the question ,

x/ 5/2 - x / 7/2 = 12/60

(difference between two times = 6 + 6= 12min)

= 2x/5 - 2x/7 = 1/5

14x - 10x = 7

4x = 7

X = 7/4 km

5. A person can walk a certain distance and drive back in 6 h. He can also walk both ways in 10 h. how

much time will he take to drive both ways?

1) 2 h 2) 2 ½ h 3) 5 ½ 4) 4 h 5) None of these

Solution: (1).

Since, he takes 10 h to walk both ways, the number of hours to walk one way for him will be 5. If he

walks one way and drives back the same way it takes him 6 h which means that the number of h taken o

drive one way is 6 – 5 = 1 h. Thus, number of hours to drive both ways will be 2.

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