**Advertisements**

1. The probability that a man will be alive for 10 more years is ¼ and the probability that his wife will

alive for 10 more years is 1/3. The probability that none of them will be alive for 10 more years, is

1) 5/12 2) 1/2 3) 7/12 4) 11/12 5) None of these

Solutions : (2)

Required probability = P (Ä€) x P (B)

= ( 1 – ¼ ) x ( 1- 1/3 ) = ¾ x 2/3 = ½

2. In a lottery 10000 tickets are sold and ten prizes are awarded. What is the probability of not getting

a prize, if you buy one ticket?

1) 9/10000 2) 9/10 3) 999/1000 4) 9999/10000 5) None of these

Solution: (3)

Total lottery tickets = 10000

Total prize in the lottery = 10

Therefore probability of getting a prize = 10/10000 = 1/1000

Now, probability of not getting a prize = 1 – probability of getting a prize

= 1 – 1/1000 = 999/1000

3. Two persons A and B appear in an interview for two vacancies. If the probabilities of their

selections are ¼ and 1/6, respectively, then the probability that none of them is selected , is

1) 5/8 2) 5/12 3) 1/12 4) 1/24 5) None of these

Solutions : (1)

Required probability = = P (Ä€) x P (B)

= ( 1- ¼) ( 1 - 1/6) = ¾ x 5/6 = 5/8

4. The probabilities of solving a problem by three students A, B and C are ½, 1/3 and ¼, respectively.

The probability that the problem will be solved, is

1) 1/4 2) 1/2 3) 3/4 4) 1/3 5) None of these

Solutions : (3).

First, we find the probability of not solving the problem.

P (A) x P (B) x P (C)

= ( 1 – ½) x ( 1- 1/3) x ( 1 – ¼)

= ½ x 2/3 x ¾ = ¼

Therefore required probability = 1- ¼ = ¾

5. A dice is rolled three times and sum of three numbers appearing on the uppermost face is 15. The

chance that the first roll was four is

1) 2/5 2) 1/5 3) 1/6 4) None of these 5) Cannot be determined

Solutions : (4)

Total number of favourable outcomes n(S) = 63 = 216

Combinations of outcomes for getting sum of 15 on uppermost face = (4,5,6),

(5,4,6),(6,5,4),(5,6,4),(4,6,5),(6,4,5),(5,5,5),(6,6,3),(6,3,6),(3,6,6)

Now, outcomes on which first roll was a four, n(E) = (4,5,6),(4,6,5)

Therefore P(E) = n(E)/n(S) = 2/216 = 1/108

Also read

IBPS PO CWE V Notification out

IBPS RRB CWE IV Notification released

IBPS PO Preliminary Practice Set Download Here

**Advertisements**

## 0 comments:

## Post a Comment